I have been in school for several years, so I have visited all messes here. Now I have lost intersts in all of the foods. So when during the meal time, I don’t know which mess I should go to. So I came up with a solution.

There are 4 messes in our school, I number them from 0 to 3. Then I says “Big Bing Small Jiang, Point Who Is Who!”, when I say the first word I point to the mess which is numbered 0, when I say the i-th (i>1) word I point to the mess whose number is one larger than the previous one. In case of the number of previous mess is 3, I will point to 0 again. I will go to the mess which I point to last time. Thus in this case I will go to the mess which is numbered 3. The following table explains the course of my solution to this case.

$\begin{array} {|c|c|c|c|}

\hline

\quad \text{ Word I say} \quad &\quad \text{ Big} \quad &\quad \text{ Bing} \quad &\quad \text{ Small} \quad &\quad \text{ Jiang} \quad &\quad \text{ Point} \quad &\quad \text{ Who} \quad &\quad \text{ Is} \quad &\quad \text{ Who} \quad\\

\hline

\hline

\quad \text{ Mess id I point to} \quad &\quad \text{ 0} \quad &\quad \text{ 1} \quad &\quad \text{ 2} \quad &\quad \text{ 3} \quad &\quad \text{ 0} \quad &\quad \text{ 1} \quad &\quad \text{ 2} \quad &\quad \text{ 3} \quad\\

\hline

\end{array}\\

$

I will go to university after several days, I have heard that there are so many messes in it. So I will apply my solution again. Surpose there are n messes which are numberd through 0 to n-1, and I will say m words. When I say the first word I point to the mess which is numbered 0, when I say the i-th (i>1) word I point to the mess whose number is one larger than the previous one. In case of the number of previous mess is n-1, I will point to 0 again. I will go to the mess which I point to last time. So which mess will I point to?.

It is so time-consuming to count it through manual work. So I want you to write a program to help me. Would you help me?

There are 4 messes in our school, I number them from 0 to 3. Then I says “Big Bing Small Jiang, Point Who Is Who!”, when I say the first word I point to the mess which is numbered 0, when I say the i-th (i>1) word I point to the mess whose number is one larger than the previous one. In case of the number of previous mess is 3, I will point to 0 again. I will go to the mess which I point to last time. Thus in this case I will go to the mess which is numbered 3. The following table explains the course of my solution to this case.

$\begin{array} {|c|c|c|c|}

\hline

\quad \text{ Word I say} \quad &\quad \text{ Big} \quad &\quad \text{ Bing} \quad &\quad \text{ Small} \quad &\quad \text{ Jiang} \quad &\quad \text{ Point} \quad &\quad \text{ Who} \quad &\quad \text{ Is} \quad &\quad \text{ Who} \quad\\

\hline

\hline

\quad \text{ Mess id I point to} \quad &\quad \text{ 0} \quad &\quad \text{ 1} \quad &\quad \text{ 2} \quad &\quad \text{ 3} \quad &\quad \text{ 0} \quad &\quad \text{ 1} \quad &\quad \text{ 2} \quad &\quad \text{ 3} \quad\\

\hline

\end{array}\\

$

I will go to university after several days, I have heard that there are so many messes in it. So I will apply my solution again. Surpose there are n messes which are numberd through 0 to n-1, and I will say m words. When I say the first word I point to the mess which is numbered 0, when I say the i-th (i>1) word I point to the mess whose number is one larger than the previous one. In case of the number of previous mess is n-1, I will point to 0 again. I will go to the mess which I point to last time. So which mess will I point to?.

It is so time-consuming to count it through manual work. So I want you to write a program to help me. Would you help me?

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