# Operation the Sequence

Time Limit: 3000/1500 MS (Java/Others)

Memory Limit: 32768/32768 K (Java/Others)

## Description

You have an array consisting of n integers: $a_1=1, a_2=2, a_3=3, \ldots, a_n=n$. Then give you m operators, you should process all the operators in order. Each operator is one of four types:
Type1: O 1 call fun1();
Type2: O 2 call fun2();
Type3: O 3 call fun3();
Type4: Q i query current value of a[i], this operator will have at most 50.
Global Variables: a[1…n],b[1…n];
fun1() {
index=1;
for(i=1; i<=n; i +=2)
b[index++]=a[i];
for(i=2; i<=n; i +=2)
b[index++]=a[i];
for(i=1; i<=n; ++i)
a[i]=b[i];
}
fun2() {
L = 1;R = n;
while(L<R) {
Swap(a[L], a[R]);
++L;--R;
}
}
fun3() {
for(i=1; i<=n; ++i)
a[i]=a[i]*a[i];
}

## Input

The first line in the input file is an integer $T(1 \leq T \leq 20)$, indicating the number of test cases.
The first line of each test case contains two integer $n(0<n \leq 100000)$, $m(0<m \leq 100000)$.
Then m lines follow, each line represent an operator above.

## Output

For each test case, output the query values, the values may be so large, you just output the values mod 1000000007(1e9+7).

## Sample Input

1 3 5 O 1 O 2 Q 1 O 3 Q 1

2 4

heyang

## Source

BestCoder Round #13