# Magic Potion

Time Limit: 2000/1000 MS (Java/Others)

Memory Limit: 65535/32768 K (Java/Others)

## Description

In a distant magic world, there is a powerful magician aswmtjdsj. One day,aswmtjdsj decide to teach his prentice ykwd to make some magic potions. The magic potion is made by 8 kinds of materials, what aswmtjdsj need to do is to tell ykwd how many each kind of materials is required. In order to prevent others from stealing these formulas, he decide to encrypt the formula. Assuming the amount of the eight kinds of materials are x1, x2, ... x8, aswmtjdsj will use a number m to encrypt, and finally tell ykwd nine numbers:x1 xor m, x2 xor m ,...., x8 xor m, (x1 + x2 +...+ x8) xor m . ykwd is too lazy,however,to calculate the value of the number m, so he asks you to help him to find the number m.

## Input

The first line is an integer t, the number of test cases.
Each of the next t lines contains 9 integers, respectively, x1 xor m, x2 xor m ,...., x8 xor m, (x1 + x2 +...+ x8) xor m, each of the 9 numbers is less or equal to 231-1.

## Output

For each test case you should output the value of m in a single line, you can assume that 0 <= m <= 231-1.

## Sample Input

2
1 2 3 4 5 6 7 8 36
5 5 5 5 5 5 5 5 123

## Sample Output

0
11

Hint
The XOR operation takes two bit patterns of equal length and performs the logical XOR operation on each pair of corresponding bits.
The result of each digit is 1 if the two bits are different, and 0 if they are the same.
For example:
0101 (decimal 5)
XOR 0011 (decimal 3)
= 0110 (decimal 6)


lcy

## Source

2011百校联动“菜鸟杯”程序设计公开赛