Simple Computer

Time Limit: 1000 mSec

Memory Limit: 32768 KB

Description

You are to write an interpreter for a simple computer. This computer uses a processor with a small number of machine instructions. Furthermore, it is equipped with 32 byte of memory, one 8-bit accumulator (accu) and a 5-bit program counter (pc). The memory contains data as well as code, which is the usual von Neumann architecture.

The program counter holds the address of the instruction to be executed next. Each instruction has a length of 1 byte - the highest 3 bits define the type of instruction and the lowest 5 bits define an optional operand which is always a memory address (xxxxx). For instructions that don't need an operand the lowest 5 bits have no meaning (-----). Here is a list of the machine instructions and their semantics:

000xxxxx   STA x   store the value of the accu into memory byte x 001xxxxx   LDA x   load the value of memory byte x into the accu 010xxxxx   BEQ x   if the value of the accu is 0 load the value x into the pc 011-----   NOP     no operation 100-----   DEC     subtract 1 from the accu 101-----   INC     add 1 to the accu 110xxxxx   JMP x   load the value x into the pc 111-----   HLT     terminate program

Input

The input file contains several test cases. Each test case specifies the contents of the memory prior to execution of the program. Byte 0 through 31 are given on separate lines in binary representation. A byte is denoted by its highest-to-lowest bits. Input is terminated by EOF.

Output

For each test case, output on a line the value of the accumulator on termination in binary representation, again highest bits first.

Sample Input

00111110
10100000
01010000
11100000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00111111
10000000
00000010
11000010
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
11111111
10001001

Sample Output

10000111

Hint

Source


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