Polycarp is a music editor at the radio station. He received a playlist for tomorrow, that can be represented as a sequence *a*_{1}, *a*_{2}, ..., *a*_{n}, where *a*_{i} is a band, which performs the *i*-th song. Polycarp likes bands with the numbers from 1 to *m*, but he doesn't really like others.

We define as *b*_{j} the number of songs the group *j* is going to perform tomorrow. Polycarp wants to change the playlist in such a way that the minimum among the numbers *b*_{1}, *b*_{2}, ..., *b*_{m} will be as large as possible.

Find this maximum possible value of the minimum among the *b*_{j} (1 ≤ *j* ≤ *m*), and the minimum number of changes in the playlist Polycarp needs to make to achieve it. One change in the playlist is a replacement of the performer of the *i*-th song with any other group.

The first line of the input contains two integers *n* and *m* (1 ≤ *m* ≤ *n* ≤ 2000).

The second line contains *n* integers *a*_{1}, *a*_{2}, ..., *a*_{n} (1 ≤ *a*_{i} ≤ 10^{9}), where *a*_{i} is the performer of the *i*-th song.

In the first line print two integers: the maximum possible value of the minimum among the *b*_{j} (1 ≤ *j* ≤ *m*), where *b*_{j} is the number of songs in the changed playlist performed by the *j*-th band, and the minimum number of changes in the playlist Polycarp needs to make.

In the second line print the changed playlist.

If there are multiple answers, print any of them.

Input4 2

1 2 3 2Output2 1

1 2 1 2Input7 3

1 3 2 2 2 2 1Output2 1

1 3 3 2 2 2 1Input4 4

1000000000 100 7 1000000000Output1 4

1 2 3 4

In the first sample, after Polycarp's changes the first band performs two songs (*b*_{1} = 2), and the second band also performs two songs (*b*_{2} = 2). Thus, the minimum of these values equals to 2. It is impossible to achieve a higher minimum value by any changes in the playlist.

In the second sample, after Polycarp's changes the first band performs two songs (*b*_{1} = 2), the second band performs three songs (*b*_{2} = 3), and the third band also performs two songs (*b*_{3} = 2). Thus, the best minimum value is 2.

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